Diketahui ²log 3=a.Tentukanlah a. ²log 9 b.27log 4 c. ⅛log 9 d. √3log 1/16 mohon bantuannya

²log3 = a
³log2 = 1/a

a) ²log9 = ²log3² = 2²log3 = 2a
b) ²⁷log4 = 2/3 ³log2 = 2/3.1/a = [tex] \frac{2}{3a} [/tex]
c) 1/8log9 = -2/3 ²log3 = -2a/3
d) √3log1/16 = -8 ³log2 = -8 . 1/a = [tex] \frac{-8}{a} [/tex]