Integral (4x^6 - 3x^5 - 8 / x^7) dx

integral

gunakan ∫ axⁿ  dx =  a/(n+1)  xⁿ⁺¹ + c

∫(4x⁶ - 3x⁵ -8) /(x⁷) dx
=  ∫ (4x⁶ - 3x⁵ -8)x⁻⁷ dx
=  ∫ 4x⁻¹ - 3x⁻² - 8x⁻⁷ dx
= 4/(-1+1) x⁻¹⁺¹ - 3/(-2+1) x⁻²⁺¹ - 8/(-7+1) x⁻⁷⁺¹ +c
= 4/(0) x⁰  + 3 x⁻¹ + 8/6 x⁻⁶
= 4 ln x   + 3/x + 4/(3x⁶)