5²(1/125)pangkat min 1 : 25

[tex]5^2 \times( \frac{1}{125}) ^{-1} \div 25^2\\ = 5^2 \times (\frac{1}{5^3}) ^{-1} \div (5^2)^2\\ = 5^2 \times (\frac{1}{5^3}) ^{-1} \div 5^{2 \times 2} \\ = 5^2 \times \frac{1}{5 ^{-3} }\div5^4\\ = 5^2 \times 5^3 \div 5^4\\ = 5 ^{2+3-4}\\ = 5^1\\ \bold{=5 }[/tex]