hitunglah: 2^2 + 4^2 + 6^2+...+100^2
Matematika
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Pertanyaan
hitunglah:
2^2 + 4^2 + 6^2+...+100^2
2^2 + 4^2 + 6^2+...+100^2
1 Jawaban
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1. Jawaban DB45
bilangan eksponen
A = 2² + 4² + 6² + ... +100²
A = 2² (1² + 2² + 3² +...+50²)
A = 4 p
misal p =1² +2²+3² +...+50²
p = 1/6(n)(n+1)(2n+1)
n = 50
p = 1/6 (50)(51)(101)
p = 42.925
.
A= 4p = 4(42.925)
A = 171.700