Matematika

Pertanyaan

Integral (6x pangkat 2 - 3) dx

1 Jawaban

  • [tex] \int\limits {6x^2-3} \, dx \\ = \frac{6}{2+1} x^{2+1}- \frac{3}{1} x^{1}+C \\ = \frac{6}{3} x^{3}-3x + C\\ \bold{=2 x^{3}-3x +C } [/tex]

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