Integral (x+3)(x-3)dx

[tex]\int\limits {(x+3)(x-3)} \, dx \\ =\int\limits {x^2-9} \, dx\\ =\frac{1}{2+1} x^{2+1}- \frac{9}{1} x^{1}+C\\ \bold {= \frac{1}{3} x^{3}-9x+C }[/tex]

Materi integral

= int (x^2-9) dx
= 1/3 x^3 - 9x + C