persamaan sistem perdasamaan linear y=4×+2 y=x2 +3×-10
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persamaan sistem perdasamaan linear y=4×+2 y=x2 +3×-10
1 Jawaban
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1. Jawaban Anonyme
Bab Persamaan Linear
Matematika SMA Kelas X
x² + 3x - 10 = 4x + 2
x² + 3x - 4x - 10 - 2 = 0
x² - x - 12 = 0
(x + 3) (x - 4) = 0
x + 3 = 0
x = - 3
y = 4x + 2
y = 4 . (-3) + 2
y = -12 + 2
y = -10 → (-3, -10)
x - 4 = 0
x = 4
y = 4x + 2
y = 4 . 4 + 2
y = 16 + 2
y = 18 → (4,18)
HP = {(-3, -10), (4, 18)}