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Pertanyaan

keempat bilangan kuantum dari 12Mg2+ 13Al3+ 19K+

1 Jawaban

  • 12Mg2+ = 10Mg = 1s2 2s2 2p6
    n = 2, l = 1 , m =+1 , s= -1/2
    13Al3+ = 10Al = 1s2 2s2 2p6
    n = 2, l = 1 , m =+1 , s= -1/2
    19k+ = 18K=1s2 2s2 2p6 3s2 3p6
    n = 3, l = 1 , m =+1 , s= -1/2


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