Matematika

Pertanyaan

tolong dijawab yah !!
tolong dijawab yah !!

2 Jawaban

  • `15
    (1 + cot² B)/ (cot B sec² B) = cot B
    ruas kliri
    (1 + cot² B)/ (cot B sec² B) =
    = csc² B/ { cot B sec² B)
    = ( 1/sin² B) / ( cos B/sin B . 1/(cos² B)}
    = (1/sin² B ) ( 1/ sin B . cos B)
    = (1/ sin² B) (sin B cos B)
    = (cos B)/(sin B)
    = cot B

    16
    sin⁴ a (cot⁴ a -1) =  2 cos² a - 1
    ruas kiri
    sin⁴a (cot⁴a - 1) =
    = sin⁴ a ( cos⁴ a/sin⁴ a  - 1)
    = cos⁴ a - sin⁴ a
    = (cos² a + sin² a)(cos² a - sin² a)
    = 1 (cos² a - sin² a)
     = cos² a - (1 - cos² a)
    = 2 cos² a - 1

    17.
    (tan  a - 1)/(tan a +1). (sin a + cos a)/(sin a - cos a) = 1
    ruas kiri
    (tan a -1)/(tan a +1). (sin a + cos a)/(sin a - cos a)=
    ..
    tan a - 1 = (sin a/cos a -1)= (sin a - cos a)/cos a
    tan a + 1 = (sin a /cos a +1) = (sin a + cos a )/ cos a
    tan a - 1/ tan a+1 =  (sin a - cos a )/(sin a + cos a)
    .
    {(tan a -1)/(tan a +1)} {(sin a + cos a)/(sin a - cos a)}=
    = {(sin a - cos a)/ (sin a + cos a)}{sin a + cos a)/(sin a - cos a)}
    = (sin a -cos a)(sin a + cos a)/ (sin a +cos a)(sin a - cos a)
    = 1.
  • Kelas : XI
    Pelajaran : Matematika
    Kategori : Pembuktian Identitas Trigonometri

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