Tuliskan hasil dari integral(x-3)²dx

dijabarin dulu
integral (x - 3)(x - 3) dx
(x² - 6x + 9) dx
= (1 / 2+1)x^(2+1) - (6 / 1+1)x^(1+1) + 9x + C
= ⅓x³ - 3x² + 9x + C

integral (x-3)^2 dx =
misal :
u=x-3
du= 1 dx
dx = du
maka :
integral (x-3)^2 dx = integral (u^2) du
= 1/3 u^3 + C
= 1/3 (x-3)^3+ C